(2x-5)^2/3=16

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Solution for (2x-5)^2/3=16 equation:


x in (-oo:+oo)

((2*x-5)^2)/3 = 16 // - 16

((2*x-5)^2)/3-16 = 0

((2*x-5)^2)/3+(-16*3)/3 = 0

(2*x-5)^2-16*3 = 0

4*x^2-20*x-23 = 0

4*x^2-20*x-23 = 0

4*x^2-20*x-23 = 0

DELTA = (-20)^2-(-23*4*4)

DELTA = 768

DELTA > 0

x = (768^(1/2)+20)/(2*4) or x = (20-768^(1/2))/(2*4)

x = (16*3^(1/2)+20)/8 or x = (20-16*3^(1/2))/8

(x-((20-16*3^(1/2))/8))*(x-((16*3^(1/2)+20)/8)) = 0

((x-((20-16*3^(1/2))/8))*(x-((16*3^(1/2)+20)/8)))/3 = 0

((x-((20-16*3^(1/2))/8))*(x-((16*3^(1/2)+20)/8)))/3 = 0 // * 3

(x-((20-16*3^(1/2))/8))*(x-((16*3^(1/2)+20)/8)) = 0

( x-((16*3^(1/2)+20)/8) )

x-((16*3^(1/2)+20)/8) = 0 // + (16*3^(1/2)+20)/8

x = (16*3^(1/2)+20)/8

( x-((20-16*3^(1/2))/8) )

x-((20-16*3^(1/2))/8) = 0 // + (20-16*3^(1/2))/8

x = (20-16*3^(1/2))/8

x in { (16*3^(1/2)+20)/8, (20-16*3^(1/2))/8 }

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